How do you write an equation for a line that is parallel to #y=3x+7# and passes through (2,10)?

1 Answer
Nov 20, 2016

Answer:

#y=3x+4#

Explanation:

#y=mx+b#

Where #m# is the slope and #b# is the y intercept

The slope of the given equation, #y=3x+7# is #3#

So, to write an equation parallel to the given equation and set of points, use point slope form and the slope of #3#:

#y-y_1=m(x-x_1)#

Where #(2,10)=>(x_1,y_1)# and #m=3#

#y-10=3(x-2)#

Distribute the #3# throughout the set of parenthesis

#y-10=3x-6#

Perform the opposite operation to isolate #y# by adding #10# on both sides of the equation

#y=3x+4#

As you can see, the slope of this line is #3#, which means that the two equations are parallel to each other