# How do you write an equation for the line parallel to 2x-y=4 that goes through (8, -12) in slope-intercept form?

Apr 3, 2015

We first write $2 x - y = 4$ in slope-intercept form:

$2 x - y = 4 \to$ add $y$ and subtract $4$ on both sides
$2 x - 4 = y \to y = 2 x - 4$ where $2$ is the slope

Now fill in $\left(8 , - 12\right)$ ($b$ is the new $y$-intercept)

$y = 2 x + b \to - 12 = 2 \cdot 8 + b \to b = - 28$

So the new equation is: $y = 2 x - 28$