# How do you write an equation in slope-intercept form for a line parallel to y = -5 that passes through the point (-1,-8)?

$y = - 8$
Slope intercept form is $y = m x + b$ where $m$ = slope, and $b = y$intercept $\left(0 , b\right)$.
When a line is in the form $y = - 5$, it has $m = 0$, therefore the line is a horizontal line. Horizontal lines have different values of $x$, but the same $y$-value. The line passes through points such as $\left(- 1 , - 5\right) , \left(0 , - 5\right) , \left(2 , - 5\right) , \left(4 , - 5\right)$.
A line that is parallel has the same slope: $m = 0$. It is also a horizontal line. To pass through $\left(- 1 , - 8\right)$ the line must be $y = - 8$