Question

How do you write an equation in slope-intercept form of the line that passes through the given points (2,6) and (-4,-2)?

Answer 1

The equation of the line in slope-intercept form is `y=4/3x+10/3`

Explanation:

The slope of the line is `(y_2-y_1)/(x_2-x_1)=(-2-6)/(-4-2) =(-8)/(-6)=4/3`. Let the equation of the line in slope-intercept form is `y=mx+c :. y= 4/3x+c` The point `(2,6)` will satisfy the equation of the line `:.6=(4/3)*2+c:. c=6-(8/3)=10/3`Hence the equation of the line in slope-intercept form is `y=4/3x+10/3`[Ans]