How do you write an equation in slope-intercept form of the line that passes through the given points (2,6) and (-4,-2)?

1 Answer
Aug 26, 2016

The equation of the line in slope-intercept form is y=4/3x+10/3

Explanation:

The slope of the line is (y_2-y_1)/(x_2-x_1)=(-2-6)/(-4-2) =(-8)/(-6)=4/3. Let the equation of the line in slope-intercept form is y=mx+c :. y= 4/3x+c The point (2,6) will satisfy the equation of the line :.6=(4/3)*2+c:. c=6-(8/3)=10/3 Hence the equation of the line in slope-intercept form is y=4/3x+10/3[Ans]