How do you write an equation in standard form for a line with y- intercept of 3/2 and slope of m = 1/2?

Jun 1, 2015

In slope-intercept form, a line with y-intercept of $\frac{3}{2}$ and a slope of $m = \frac{1}{2}$ would be written as
$\textcolor{w h i t e}{\text{XXXXX}}$$y = \frac{1}{2} x + \frac{3}{2}$

Standard form is (normally)
$\textcolor{w h i t e}{\text{XXXXX}}$$A x + B y = C$ where $A \ge 0 \mathmr{and} A \epsilon \mathbb{Z}$

Converting to standard form.
Multiply everything by 2 to clear the fractions
$\textcolor{w h i t e}{\text{XXXXX}}$$2 y = 1 x + 3$
Subtract $2 y + 3$ from both sides (and flip the sides)
$\textcolor{w h i t e}{\text{XXXXX}}$$1 x - 2 y = - 3$
$\textcolor{w h i t e}{\text{XXXXX}}$$\textcolor{w h i t e}{\text{XXXXX}}$which is in standard form