How do you write an equation in standard form given point (-2,4) and slope -3/2?

1 Answer
Jim G.
Jun 3, 2017

#3x+2y=2#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.

#"first express the equation in "color(blue)"point-slope form"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here " m=-3/2" and " (x_1,y_1)=(-2,4)#

#rArry-4=-3/2(x+2)larrcolor(red)" in point-slope form"#

#"rearrange terms into standard form"#

#y-4=-3/2x-3#

#rArr3/2x+y=1larr" multiply through by 2"#

#rArr3x+2y=2larrcolor(red)" in standard form"#

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