How do you write an equation in standard form given point (-2,5) and slope 1?

2 Answers
May 7, 2017

y = x+7

Explanation:

  • Use the formula y=mx+c
    m = gradient of graph
    c= y intercept

  • Substitute y,m and x in equation to find c
    #5=1*-2 +c#
    #5=-2+c#
    7=c

  • Replace m and c with numbers found
    Therefore equation is y = x + 7

May 7, 2017

#x-y=-7#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"begin by expressing the equation in "color(blue)"point-slope form"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here " m=1" and " (x_1,y_1)=(-2,5)#

#y-5=1(x-(-2))#

#rArry-5=x+2larrcolor(red)" in point-slope form"#

#"subtract y from both sides"#

#cancel(y)cancel(-y)-5=x+2-y#

#rArr-5=x+2-y#

#"subtract 2 from both sides"#

#-5-2=xcancel(+2)cancel(-2)-y#

#rArr-7=x-y " or "#

#x-y=-7larrcolor(red)" in standard form"#