How do you write an equation in standard form when given slope and point on line (1, 5), m = -3?

1 Answer
Jul 28, 2017

See a solution process below:

Explanation:

First, we can use the point-slope formula to write an equation for the line. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

#(y - color(red)(5)) = color(blue)(-3)(x - color(red)(1))#

We can now solve for the Standard Form of the equation. The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

#y - color(red)(5) = (color(blue)(-3) xx x) - (color(blue)(-3) xx color(red)(1))#

#y - color(red)(5) = -color(blue)(3)x - (-3)#

#y - color(red)(5) = -color(blue)(3)x + 3#

#y - color(red)(5) + 5 = -color(blue)(3)x + 3 + 5#

#y - 0 = color(blue)(3)x + 8#

#3x + y = 3x + color(blue)(3)x + 8#

#3x + y = 0 + 8#

#color(red)(3)x + color(blue)(1)y = color(green)(8)#