# How do you write an equation of a line given (-3, 6) and has slope 1/3?

Jun 17, 2018

$y = \frac{1}{3} x + 7$

#### Explanation:

graph{1/3x+7 [-12.81, 15.66, -2.11, 12.12]}
You would want the line on the form $y = a x + b$,
where a is the slope.
Therefore $a = \frac{1}{3}$.

You want the line to go through (-3, 6), i.e. y=6 for x=-3
Therefore
$6 = \frac{1}{3} \left(- 3\right) + b$
This gives b=7
Your line, therefore, is $y = \frac{1}{3} x + 7$