How do you write an equation of a line given point (-6, 3) and has slope 2?
1 Answer
Oct 7, 2016
Explanation:
The equation of a line in
#color(blue)"point-slope form"# is
#color(red)(bar(ul(|color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"# here m = 2 and
#(x_1,y_1)=(-6,3)# substitute these values into the equation
#y-3=2(x-(-6))#
#rArry-3=2(x+6)rArry-3=2x+12#
#rArry=2x+15larr" in slope-intercept form"#