How do you write an equation of a line given slope of m=-1/3 and passes through the point (-1,1)?

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Answer 1 · 2018-03-04T22:36:06

#y=-1/3x+2/3#

Use point slope form: #y-y_1=m(x-x_1)# You can use this equation if you have the given point and the slope of the line. Hope this helps!

Answer 2 · 2018-03-04T22:36:30

The equation of the line is #y=-1/3x+2/3#.

You can write the line in point-slope form, which uses a point and slope to make an equation. It looks like this:

#color(white)=>y-y_1=m(x-x_1)#

where #m# is the slope and #(x_1, y_1)# is a point on the line.

Now we can apply this to our problem. We have a slope of #-1/3# and a point #(-1,1)#. Plug in the values to the point-slope formula:

#color(white)=>y-y_1=m(x-x_1)#

#=>y-1=-1/3(x-(-1))#

#color(white)=>y-1=-1/3(x+1)#

#color(white)=>y-1=-1/3x-1/3#

#color(white)=>y=-1/3x+2/3#

That's the equation of the line. Here's what it looks like:

graph{-(1/3)x+(2/3) [-8.89, 8.89, -4.444, 4.445]}