How do you write an equation of a line going through (7,1) parallel to y=-x+3?

1 Answer
Oct 10, 2016

Answer:

#y=-x+8#

Explanation:

Equations that are parallel have the same slope.

The standard equation of an equation is written through slope intercept form, which is #y=mx+b# where m is your slope and b is the y intercept

So, in the equation provided, -1 is the slope.

To write an equation when given a slope and points, you use point slope form, which is #y-y_1=m(x-x_1)#

#y_1# is the y in the set of points you are given, same with #x_1#

So, #y_1=1# and #x_2=7#

As stated before, m is the slope, and the slope is given as -1

Plug in the numbers into the equation

#y-1=-1(x-7)#

Distribute -1 throughout the parenthesis

#y-1=-x+7#

Add 1 on both sides of the equation

#y=-x+8#

And there you have a equation parallel to #y=-x+3#