How do you write an equation of a line parallel to the graph of 2x+5y=3 and the x-intercept is -2?

1 Answer
Apr 9, 2016

Answer:

#2x+5y=-4#

Explanation:

Any equation of the form #Ax+By=C# has a slope of #m=-A/B#

Therefore #2x+5y=3# has a slope of#( -2/5)#

All parallel lines have the same slope.

If a line has an x-intercept of #(-2)#
then #(x,y)=(-2,0)# is a point on the line.

Using the slope definition:
#color(white)("XXX")(y-0)/(x-(-2))=(-2/5)#

#color(white)("XXX")y=(-2/5)(x+2)#

#color(white)("XXX")5y = -2x-4#

#color(white)("XXX")2x+5y=-4# (standard linear form)