How do you write an equation of a line passes through (-1,-5) and is parallel to 3x+y=+8?

Mar 23, 2018

$y + 5 = - 3 \left(x + 1\right)$

Explanation:

First, find the slope of the line that it is parallel to, as this line will have the same slope.
$3 x + y = 8$
$y = - 3 x + 8$
Therefore, $m = - 3$
We can use point slope form to plug in the coordinates and the slope.
$y - {y}_{1} = m \left(x - {x}_{1}\right)$
$y + 5 = - 3 \left(x + 1\right)$