# How do you write an equation of a line passing through (2, 5), perpendicular to #x - 5y = -10#?

##### 1 Answer

Feb 28, 2017

#### Answer:

#### Explanation:

Let's first look at the the line

And so slope,

To find the perpendicular slope, we take the negative inverse, which gives us

To find the line passing through the point

For comparison, let's put this into slope-intercept form:

And we can graph them both:

graph{(y-(-5x+15))(y-(1/5x+2))=0 [-10, 10, -8, 8]}