How do you write an equation of a line that passes through the point (-8, -5) and has a slope of -5/4?

1 Answer
Jan 11, 2017

#y=-5/4x-15#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here " m=-5/4" and " (x_1,y_1)=(-8,-5)#

substituting these values into the equation.

#y-(-5)=-5/4(x-(-8))#

#rArry+5=-5/4(x+8)larr" in point-slope form"#

distributing and simplifying gives the equation in an alternative form.

#y+5=-5/4x-10#

#rArry=-5/4x-15larr" in slope-intercept form"#