How do you write an equation of a line through (6, 2); parallel to $4 x - y = 3$ $4x-y=3$ ?

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How do you write an equation of a line through (6, 2); parallel to $4 x - y = 3$ $4x-y=3$ ?

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Answer 1 · 2016-12-05T11:15:03

I got: $4 x - y = 22$ $4x-y=22$

Explanation:

We can use the general expression for a line through a point of coordinates $(x_{0}, y_{0})$ $(x_0,y_0)$ and slope $m$ $m$ as:

$y - y_{0} = m (x - x_{0})$ $y-y_0=m(x-x_0)$

The slope must be the same of the slope of the original line in order to be parallel.

The original line can be written (collecting $y$ $y$ ) as:
$y = 4 x - 3$ $y=4x-3$
where the slope will be: $m = 4$ $m=4$ (the coefficient of $x$ $x$ ):
so we have:
$y - 2 = 4 (x - 6)$ $y-2=4(x-6)$
$y = 4 x - 24 + 2$ $y=4x-24+2$
$y = 4 x - 22$ $y=4x-22$
or
$4 x - y = 22$ $4x-y=22$

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How do you write an equation of a line through (6, 2); parallel to $4 x - y = 3$ $4x-y=3$ ?

1 Answer

Explanation:

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How do you write an equation of a line through (6, 2); parallel to $4 x - y = 3$ $4x-y=3$ ?