How do you write an equation of a line with point (-1,4) and slope -1?

1 Answer
Nov 14, 2016

#y = -x + 3#

Explanation:

The general equation of the straight line is :
#" "#
#y - y_0 = a(x - x_0)#
#" "#
# a " "#is the slope.
#" "#
#(x_0,y_0)" "#is the point the straight line passes through.
#" "#
Here #a =-1" " x_0=-1" "and y_0 = 4#
#" "#
#y - 4 = -1(x - (-1))#
#" "#
#rArr y - 4 = -1(x + 1)#
#" "#
#rArr y - 4 = -x - 1#
#" "#
#rArr y = -x -1 +4#
#" "#
#rArr y = -x + 3#
#" "#
#" "#
Hence ,#" "y = -x + 3#