How do you write an equation of a line with point (2,5) and slope -2?

1 Answer
Nov 12, 2016

#y=-2x+9#

Explanation:

The equation of a line in #color(blue)"point-slope form" # is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

here # m=-2" and " (x_1,y_1)=(2,5)#

substitute these values into the equation.

#rArry-5=-2(x-2)#

distribute the bracket and collect like terms.

#y-5=-2x+4rArry=-2x+4+5#

#rArry=-2x+9" is the equation"#