How do you write an equation of a line with slope #7# passing through the point #(-1,3)#?

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Answer 1 · 2016-11-10T08:59:01

#y =7x+10#

If you have the slope of a line and one point on the line, substitute them into the "point-slope" form of a straight line.

#m = 7 and (-1,3)#

#y-y_1 = m(x-x_1)" "larr# point-slope form

#y-3 = 7(x-(-1)#

#y -3 = 7(x+1)" "larr# multiply out and simplify

#y = 7x+7+3#

#y =7x+10#