Question

How do you write an equation of the line given (3,-6) with slope -4/3?

Answer 1

`3y=-4x-6`

Explanation:

The equstion of a straight line with slope `(m)` passing through the point `(x_1,y_1)` is given by:

`y-y_1 = m(x-x_1)`

In our example: `m=-4/3 and (x_1,y_1) = (3,-6)`

`:. (y-(-6)) = -4/3(x-3)`

`3(y+6) =-4(x-3)`

`3y+18 = -4x+12`

`3y = -4x+12-18`

`3y=-4x-6`