How do you write an equation of the line that passes through the given (3,4); m=-4?

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Answer 1 · 2016-11-15T09:18:54

#y = -4x+16#

You have 2 choices for the equation of a straight line:

Substitute into the "point-slope" form #y-y_1=m(x-x_1)# which involves one one substitution and some simplifying.
Substitute into the "slope-intercept" form to find #c# first. This involves two substitutions.

My choice is the first option. You have #m = -4 and (3,4)#

#y-y_1=m(x-x_1)" "larr# leave #x and y #
#color(white)(xx)darrcolor(white)(xx)darrcolor(white)(xx.x)darr#

#ycolor(blue)(-4) = -4(x-3)#

#y = -4x+12color(blue)(+4)#

# y = -4x+16#