How do you write an equation of #y=sinx# with pi/2 units to the right and 3.5 units up?

1 Answer
Nov 3, 2017

Answer:

#y= sin(x-pi/2)+7/2#

Explanation:

Subtracting #pi/2# from #x# will move the graph #pi/2# units to the right. Adding #pi/2# to #x# will move the graph #pi/2# units to the left.

Adding a constant to #sinx# will translate the graph up for positive value and down for a negative value.

So:

#y=sinx# becomes #y= sin(x-pi/2)+7/2#

See graphs:

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