# How do you write b^-4/b^-6 using only positive exponents?

Feb 3, 2017

${b}^{- 4} / {b}^{- 6} = {b}^{2}$

#### Explanation:

Notice
${b}^{- 4} / {b}^{- 6} = {b}^{- 4} \left(\frac{1}{b} ^ \left(- 6\right)\right)$

Also, since ${x}^{- 1} = \frac{1}{x}$, we can say

${b}^{- 4} \left(\frac{1}{b} ^ \left(- 6\right)\right) = \left(\frac{1}{b} ^ 4\right) \left({b}^{6}\right)$

And just like above

$\left(\frac{1}{b} ^ 4\right) \left({b}^{6}\right) = {b}^{6} / {b}^{4} = {b}^{6 - 4} = {b}^{2}$