How do you write in simplified radical form of #4sqrt(48)#?

1 Answer
Feb 5, 2015

You need to break down (find the prime factorization of) 48.

#4sqrt(6*8)#
#4sqrt(2*3*4*2)#
#4sqrt(2*3*2*2*2)#

Remember we are looking for pairs of two when we are looking for the square root.

We find that we have two sets of 2s. We will bring a 2 out for each set.

#4*2*2sqrt3#

Which gives me #16sqrt3#