How do you write #p(x) = |x-1| +4# as a piecewise function?

1 Answer
Apr 16, 2017

Answer:

Use the definition of the absolute value function:

#|a| = {(a; a >=0),(-a;a<0):}#

Explanation:

Given: #p(x) = |x-1| +4#

Please observe that #a = x-1# with regard to the definition:

#|x-1| = {(x-1; x-1 >=0),(1-x;x-1<0):}#

Simplify the inequalities

#|x-1| = {(x-1; x >=1),(1-x;x<1):}#

Add 4 to both sides:

#|x-1|+4 = {(x-1+4; x >=1),(1-x+4;x<1):}#

Simplify the right side and substitute #p(x)# on the left:

#p(x) = {(x+3; x >=1),(5-x;x<1):}#