# How do you write P(x) = x^3 − 7x^2 + 14x − 8 in factored form?

It is $P \left(x\right) = \left(x - 1\right) \left(x - 2\right) \left(x - 4\right)$

#### Explanation:

You check if the factors of the constant term $- 8$ are roots of the polynomial.In our case the following factors $1 , 2 , 4$ are roots of the polynomial hence

$P \left(x\right) = \left(x - 1\right) \left(x - 2\right) \left(x - 4\right)$

Another way is to analyzed it into a product of two polynomials as follows

$P \left(x\right) = \left(x + a\right) \cdot \left({x}^{2} + b x + c\right)$

and you have to find values of $a , b , c$