# How do you write the chemical equation and the K_a expression for the acid dissociation of the following acids in aqueous solution?

## ${C}_{6} {H}_{5} C O O H$ $H C {O}_{3}^{-}$

Aug 23, 2016

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#### Explanation:

${C}_{6} {H}_{5} C {O}_{2} H \left(a q\right) + {H}_{2} O r i g h t \le f t h a r p \infty n s {H}_{3} {O}^{+} + {C}_{6} {H}_{5} C {O}_{2}^{-}$

${K}_{a} = \frac{\left[{H}_{3} {O}^{+}\right] \left[{C}_{6} {H}_{5} C {O}_{2}^{-}\right]}{\left[{C}_{6} {H}_{5} C {O}_{2} H\right]}$

$H C {O}_{3}^{-} + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s C {O}_{3}^{2 -} + {H}_{3} {O}^{+}$

K_a=???

All I have done here is conserve mass and charge. The second equilibrium will lies to the left inasmuch as bicarbonate is a very indifferent acid.