How do you write the chemical equation and the #K_a# expression for the acid dissociation of the following acids in aqueous solution?

#C_6H_5COOH#
#HCO_3^-#

1 Answer
Aug 23, 2016

Answer:

Attend:

Explanation:

#C_6H_5CO_2H(aq) + H_2O rightleftharpoons H_3O^+ + C_6H_5CO_2^-#

#K_a=([H_3O^+][C_6H_5CO_2^-])/([C_6H_5CO_2H])#

#HCO_3^(-) +H_2O(l) rightleftharpoons CO_3^(2-) + H_3O^+#

#K_a=???#

All I have done here is conserve mass and charge. The second equilibrium will lies to the left inasmuch as bicarbonate is a very indifferent acid.