Question

How do you write the equation given vertex (4,3), axis of symmetry y=3, measure of latus rectrum 4, a>0?

Answer 1

`(y-4)^2=4(x-3)`. See the Socratic graph.

Explanation:

`Vertex is ( 3, 4 ), size a = ( latus rectum ) /2=4/4= 1` and the axis is `y=4 uarr`,

So, the equation is

`(y-4)^2=4(x-3)`

graph{((y-4)^2-4(x-3) ) (y-4+.001x)((x-3)^2+(y-4)^2-.4)=0 [-40, 40, -20, 20]}