How do you write the equation in point slope form given (2,5) and is parallel to y = 3x + 8?

The equation of line is $y = 3 x - 1$
Parallal lines have equal slope. The slope of the line $y = 3 x + 8$ is $3 \left[y = m x + c\right]$.Therefore the slope of the line is also $3.$
The equation of line passing through $\left(2 , 5\right)$ is $y - {y}_{1} = m \left(x - {x}_{1}\right) \mathmr{and} y - 5 = 3 \left(x - 2\right) \mathmr{and} y - 5 = 3 x - 6 \mathmr{and} y = 3 x - 6 + 5 \mathmr{and} y = 3 x - 1$[Ans]