How do you write the equation in point slope form given a line parallel to y= -2 + 3x passing through (-2,8)?

1 Answer
Nov 12, 2017

Answer:

#y-8=3(x+2)#

Explanation:

#• " Parallel lines have equal slopes"#

#y=3x-2" is in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#rArry=3x-2" has slope "m=3#

#"hence a parallel line will have slope "m=3#

#"the equation of a line in "color(blue)"point-slope form"# is.

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=3" and "(x_1,y_1)=(-2,8)#

#y-8=3(x-(-2))#

#rArry-8=3(x+2)larrcolor(red)"in point-slope form"#