Question

How do you write the equation in slope intercept form given (10,-9);m=-2?

Answer 1

`y =-2x-19`

Explanation:

Since we are provided the slope and a point on the line we can use the equation for point slope form of the equation of a line.

`y-y_1 =m(x-x_1)`

Where `m=` slope and the point is `(x_1,y_1)`

For this situation `m=-5` and a point of `(10,-9)`

`m=-2`
`x_1=10`
`y_1=-9`

`y-y_1 =m(x-x_1)`

Plug in the values
`y-(-9) =-2(x-10)`

Simplify the signs
`y+9 =-2(x+10)`

Use distributive property to eliminate the parenthesis
`y+9 =-2x-20`

Use the additive inverse to isolate the `y` value
`y cancel(+9) cancel(-9) =-2x-10-9`

Simplify the common terms
`y =-2x-19`