# How do you write the equation in slope intercept form of the line with x intercept of -8 and slope of -5/4?

##### 2 Answers

#### Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

where m represents the slope and b, the y-intercept.

#"here "m=-5/4#

#rArry=-5/4x+blarr" partial equation"#

#"to find b, substitute " (-8,0)" into the partial equation"#

#rArr0=10+brArrb=-10#

#rArry=-5/4x-10larrcolor(red)" in slope-intercept form"#

**The equation of straight line in slope intercept form is**

#### Explanation:

Given, slope

Let the equation of straight line in slope intercept form is

Where

Hence equation of straight line is

graph{-5/4x-10 [-40, 40, -20, 20]} [Ans]