# How do you write the equation in slope intercept form of the line with x intercept of -8 and slope of -5/4?

May 30, 2017

$y = - \frac{5}{4} x - 10$

#### Explanation:

$\text{the equation of a line in "color(blue)"slope-intercept form}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = m x + b} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and b, the y-intercept.

$\text{here } m = - \frac{5}{4}$

$\Rightarrow y = - \frac{5}{4} x + b \leftarrow \text{ partial equation}$

$\text{to find b, substitute " (-8,0)" into the partial equation}$

$\Rightarrow 0 = 10 + b \Rightarrow b = - 10$

$\Rightarrow y = - \frac{5}{4} x - 10 \leftarrow \textcolor{red}{\text{ in slope-intercept form}}$

May 30, 2017

The equation of straight line in slope intercept form is $y = - \frac{5}{4} x - 10$

#### Explanation:

Given, slope $m = - \frac{5}{4}$ , x - intercept = $- 8 \mathmr{and} \left(- 8 , 0\right)$

Let the equation of straight line in slope intercept form is $y = m x + c$ ,
Where $m \mathmr{and} c$ are slope and y-intercept.

$y = - \frac{5}{4} x + c$ Putting $x = - 8 \mathmr{and} y = 0$ in the equation , we get
$0 = - \frac{5}{4} \cdot - 8 + c \mathmr{and} 0 = 10 + c \mathmr{and} c = - 10$

Hence equation of straight line is $y = - \frac{5}{4} x - 10$
graph{-5/4x-10 [-40, 40, -20, 20]} [Ans]