Question

How do you write the equation in slope intercept form of the line with x intercept of -8 and slope of -5/4?

Answer 1

`y=-5/4x-10`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`"here "m=-5/4`

`rArry=-5/4x+blarr" partial equation"`

`"to find b, substitute " (-8,0)" into the partial equation"`

`rArr0=10+brArrb=-10`

`rArry=-5/4x-10larrcolor(red)" in slope-intercept form"`

Answer 2

The equation of straight line in slope intercept form is `y= -5/4x -10`

Explanation:

Given, slope `m= -5/4` , x - intercept = `-8 or (-8,0)`

Let the equation of straight line in slope intercept form is `y=mx+c` ,
Where `m and c` are slope and y-intercept.

`y = -5/4x+c` Putting `x= -8 and y=0` in the equation , we get
`0 = -5/4*-8 +c or 0 =10+c or c= -10`

Hence equation of straight line is `y= -5/4x -10`
graph{-5/4x-10 [-40, 40, -20, 20]} [Ans]