# How do you write the equation in standard form given m = -1/2 and (4,6)?

##### 1 Answer

Jan 31, 2017

#### Explanation:

The equation of a line in

#color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))#

where a is a positive integer and b, c are integers.Begin by expressing the equation in

#color(blue)"point-slope form"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#

where m represents the slope and# (x_1,y_1)" is a point on the line"#

#"here "m=-1/2" and " (x_1,y_1)=(4,6)# Substituting these values into the equation.

#y-6=-1/2(x-4)larrcolor(red)"point-slope form"# distributing, simplifying and rearranging.

#y-6=-1/2x+2#

#rArr1/2x+y-8=0# coefficient of x, that is a must be an integer.

multiplying through by 2

#rArrx+2y-16=0larrcolor(red)" in standard form"#