How do you write the equation of a line in point slope form that is parallel to y=3x-11 and goes through (9,6)?

May 6, 2015

$y = 3 x - 11$ is the equation of a line in slope-intercept form.
From this we can deduce that the slope is $m = 3$

Any line parallel to $y = 3 x - 11$ will also have a slope of $m = 3$

Slope-point form of a line is
$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$
and given the point $\left({x}_{1} , {y}_{1}\right) = \left(9 , 6\right)$

The slope-point form of the required line is
$y - 6 = 3 \left(x - 9\right)$