# How do you write the equation of a line in slope intercept, point slope and standard form given Point: (7, -2) Slope:m = 1/2?

##### 1 Answer
Mar 9, 2018

(1) Point slope form of the equation is $y + 2 = \left(\frac{1}{2}\right) \cdot \left(x - 7\right)$

(2) Slope intercept form of equation $y = \frac{x}{2} - \frac{11}{2}$

(3) Standard form $x - 2 y = 11$

#### Explanation:

$s l o p e = m = \frac{1}{2} , A \left({x}_{1} , {y}_{1}\right) = \left(7 , - 2\right)$

Slope intercept form $y = m x + c$

Point slope form $\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

Standard form of linear equation $A x + B y = C$

Known m, one point, equation of a line can be written using

$y - {y}_{1} = m \left(x - {x}_{1}\right)$ point slope form.

(1) Point slope form of the equation is $y + 2 = \left(\frac{1}{2}\right) \cdot \left(x - 7\right)$

$2 y + 4 = x - 7$

$2 y = x - 7 - 4 = x - 11$

(2) Slope intercept form of equation $y = \frac{x}{2} - \frac{11}{2}$

(3) Standard form $x - 2 y = 11$