# How do you write the equation of a line with passes through (-1, 3) and (-6, -7) in standard from?

Oct 20, 2015

$2 x - y = - 5$

#### Explanation:

From the given, we can use two-point slope form

$\left(y - {y}_{1}\right) = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} \left(x - {x}_{1}\right)$

$y - 3 = \frac{- 7 - 3}{- 6 - - 1} \left(x - - 1\right)$

$y - 3 = \frac{- 10}{-} 5 \left(x + 1\right)$

$y - 3 = 2 \left(x + 1\right)$

$y - 3 = 2 x + 2$

$- 2 x + y = 2 + 3$

$- 1 \left[- 2 x + y = 5\right] - 1$

$2 x - y = - 5$ $\rightarrow$ standard form

$2 x - y + 5 = 0$ $\rightarrow$ general form