How do you write the equation of a point slope form passing through (-2,8) and parallel to the line #5x-6y-7=0#?

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Answer 1 · 2016-12-30T10:18:49

#y = 5/6x + 29/3#

Parallel lines have the same slope.

Get the slope of the given line

#5x - 6y - 7 = 0#

#=> 6y = 5x - 7#

#=> y = 5/6x - 7/6#

#=> m = 5/6#

#y = 5/6x + b#

Get the y-intercept using the given point

#=> 8 = 5/6(-2) + b#

#=> 8 = -5/3 + b#

#=> 24 = -5 + 3b#

#=> 29 = 3b#

#=> b = 29/3#

#y = 5/6x + 29/3#