Question

How do you write the equation of the circle with Center (3, 4) and radius 6?

Answer 1

`x^2+y^2-6x-8y-11=0`

Explanation:

We have to find the equation of a circle whose center is `(3, 4)` and radius `6`.

As the distance of any point on the circle from center will always be `6`

`(x-3)^2+(y-4)^2=6^2` or

`x^2-6x+9+y^2-8y+16=36` or

`x^2+y^2-6x-8y+9+16-36=0` or

`x^2+y^2-6x-8y-11=0`