How do you write the equation of the circle with the given center and radius: Center at (3, -6); radius = 5?

Jan 2, 2016

Answer:

You can use the general telationship:
${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

Explanation:

In the above relationship $\left(h , k\right)$ are the coordinates of the center while $r$ is the radius of your circle.
You should get:

${\left(x - 3\right)}^{2} + {\left(y + 6\right)}^{2} = {5}^{2}$

Try to expand this equation by yourself to get to the equation of the circle in the form:
${x}^{2} + {y}^{2} + \ldots . = 0$