# How do you write the equation of the cosine function with an amplitude of 1/2, a period of 2pi, and a phase shift of 3pi/2?

The equation of cosine function is $y = \frac{1}{2} \cos \left(x - \frac{3 \pi}{2}\right)$
General equation is $y = A \cos \left(B x + C\right) + D$ Where "A" is amplitude; Period = $\frac{2 \pi}{B} \mathmr{and} B = 2 \pi$/piriod; phase shift is $- \frac{C}{|} B |$ here A=1/2; B=(2pi)/(2pi)=1 ; C= -(3*pi)/2:. the equation of cosine function is $y = \frac{1}{2} \cos \left(x - \frac{3 \pi}{2}\right)$ [Ans]