How do you write the equation of the cosine function with an amplitude of 1/2, a period of 2pi, and a phase shift of 3pi/2?

1 Answer
Binayaka C.
Jun 12, 2016

The equation of cosine function is #y= 1/2 cos (x- (3pi)/2) #

Explanation:

General equation is #y= A cos (Bx+C)+D # Where "A" is amplitude; Period = #(2pi)/B or B=2pi#/piriod; phase shift is #-C/|B|# here #A=1/2; B=(2pi)/(2pi)=1 ; C= -(3*pi)/2:.# the equation of cosine function is #y= 1/2 cos (x- (3pi)/2) # [Ans]

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