# How do you write the equation of the line parallel to 4x + 3y = 9 and passing through the point ( -10, 3 )?

Sep 27, 2015

4x+3y=-31

#### Explanation:

we know,
if a line is in general form $A x + B y = C$ then the slope is $m = - \frac{A}{B}$
and parallel lines have the same slope.
so for the given equation,the slope is
$m = - \frac{4}{3}$
The new line has slope $- \frac{4}{3}$ and contains the point $\left(- 10 , 3\right)$.
the general equation of line (where points and slope are given) is

y-y_"1" = m(x-x_"1");
So the equation will be
$y - 3 = - \frac{4}{3} \left(x + 10\right)$
after simplifying
$4 x + 3 y = - 31$