How do you write the equation of the line parallel to 4x + 3y = 9 and passing through the point ( -10, 3 )?

1 Answer
Sep 27, 2015

Answer:

4x+3y=-31

Explanation:

we know,
if a line is in general form #Ax+By=C# then the slope is #m=-A/B#
and parallel lines have the same slope.
so for the given equation,the slope is
#m= - 4/3#
The new line has slope #-4/3# and contains the point #(-10,3)#.
the general equation of line (where points and slope are given) is

#y-y_"1" = m(x-x_"1");#
So the equation will be
#y-3= - 4/3(x+10)#
after simplifying
#4x+3y=-31#