Question

How do you write the equation of the line parallel to 4x + 3y = 9 and passing through the point ( -10, 3 )?

Answer 1

4x+3y=-31

Explanation:

we know,
if a line is in general form `Ax+By=C` then the slope is `m=-A/B`
and parallel lines have the same slope.
so for the given equation,the slope is
`m= - 4/3`
The new line has slope `-4/3` and contains the point `(-10,3)`.
the general equation of line (where points and slope are given) is

`y-y_"1" = m(x-x_"1");`
So the equation will be
`y-3= - 4/3(x+10)`
after simplifying
`4x+3y=-31`