Question

How do you write the equation of the line parallel to the line x + 4y = 6 and passes through (-8, 5)?

Answer 1

I found `x+4y=12`

Explanation:

We can use the general relationship for the equation of a line passing through `(x_0,y_0)` and slope `m` as:
`y-y_0=m(x-x_0)`
to be parallel the slope must be the same of your original line.
We write the original line (collecting `y`) as:
`y=-1/4x+6/4`
whose slope is `-1/4`
so we can find our parallel as:
`y-5=-1/4[x-(-8)]`
`4y-20=-x-8`
so the equation will be:
`x+4y=12`