# How do you write the equation of the line with point (-6, 3) and has slope 2?

Jul 11, 2016

y = 2x +15

#### Explanation:

Since we have a point and slope, use the $\textcolor{b l u e}{\text{point-slope form}}$ to establish the equation.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right) \text{ a point}$

here m = 2 and $\left({x}_{1} , {y}_{1}\right) = \left(- 6 , 3\right)$

Substitute these values into the equation.

$\Rightarrow y - 3 = 2 \left(x - \left(- 6\right)\right)$

$\Rightarrow y - 3 = 2 \left(x + 6\right) \Rightarrow y - 3 = 2 x + 12 \Rightarrow y = 2 x + 15$