How do you write the equation of the parabola in vertex form #F(x)=x^2-2x+5#? Precalculus Geometry of a Parabola Vertex Form of the Equation 1 Answer Eddie Jun 27, 2016 #F(x) = (x-1)^2 + 5# Explanation: #F(x) = x^2 - 2x + 5# #= (x-1)^2 - 1 + 5# #= (x-1)^2 + 5# Answer link Related questions How do I convert the equation #f(x)=x^2+1# to vertex form? How do I convert the equation #f(x)=x^2+2/5x−1# to vertex form? How do I convert the equation #f(x)=x^2-4x+3# to vertex form? How do I convert the equation #f(x)=x^2-8x+15# to vertex form? How do I convert the equation #f(x)=x^2+6x+5# to vertex form? How do I convert the equation #f(x)=x^2-2x-3# to vertex form? What do #h# and #k# represent in the vertex form of a parabola's equation? How do I find the vertex of #y=(x−3)^2+4#? How do I find the vertex of #y=(x+2)^2-3#? How do I find the vertex of #y=(x+7)^2#? See all questions in Vertex Form of the Equation Impact of this question 1415 views around the world You can reuse this answer Creative Commons License