How do you write the first six terms of the sequence $a_n=(n-1)^2$ ?

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Answer 1 · 2016-10-10T06:10:44

First six terms are ${0,1,4,9,16,25}$

You can derive the $n^(th)$ term by puuting the value of $n$ in $a_n=(n-1)^2$

Hence, $a_1=(1-1)^2=0$

$a_2=(2-1)^2=1^2=1$

$a_3=(3-1)^2=2^2=4$

$a_4=(4-1)^2=3^2=9$

$a_5=(5-1)^2=4^2=16$

$a_6=(6-1)^2=5^2=25$

Hence, first six terms are ${0,1,4,9,16,25}$

How do you write the first six terms of the sequence a_n=(n-1)^2a_n=(n-1)^2?