# How do you write the hyperbola 16y^2-36x^2+9=0 in standard form?

${x}^{2} / 4 - {y}^{2} / \left(\frac{9}{16}\right) = 1$.
We rewrite the eqn. as $36 {x}^{2} - 16 {y}^{2} = 9$.
$\therefore \left(\frac{36}{9}\right) {x}^{2} - \left(\frac{16}{9}\right) {y}^{2} = 1$.
$\therefore {x}^{2} / 4 - {y}^{2} / \left(\frac{9}{16}\right) = 1$.