Question

How do you write the hyperbola `16y^2-36x^2+9=0` in standard form?

Answer 1

`x^2/4-y^2/(9/16)=1`.

Explanation:

We rewrite the eqn. as `36x^2-16y^2=9`.

`:. (36/9)x^2-(16/9)y^2=1`.

`:. x^2/4-y^2/(9/16)=1`.