# How do you write the point slope form of an equation for a lint that passes through (-6,3) with m=-2/3?

Feb 5, 2017

$\left(y - 3\right) = - \frac{2}{3} \left(x + 6\right)$

#### Explanation:

The point-slope formula states: $\left(y - \textcolor{red}{{y}_{1}}\right) = \textcolor{b l u e}{m} \left(x - \textcolor{red}{{x}_{1}}\right)$

Where $\textcolor{b l u e}{m}$ is the slope and $\textcolor{red}{\left(\left({x}_{1} , {y}_{1}\right)\right)}$ is a point the line passes through.

Substituting the information from the problem gives:

$\left(y - \textcolor{red}{3}\right) = \textcolor{b l u e}{- \frac{2}{3}} \left(x - \textcolor{red}{- 6}\right)$

$\left(y - \textcolor{red}{3}\right) = \textcolor{b l u e}{- \frac{2}{3}} \left(x + \textcolor{red}{6}\right)$