How do you write the point slope form of an equation for a lint that passes through (1,-3) with m=-5/8?

Jan 29, 2017

$\left(y + \textcolor{red}{3}\right) = \textcolor{b l u e}{- \frac{5}{8}} \left(x - \textcolor{red}{1}\right)$

Explanation:

The point-slope formula states: $\left(y - \textcolor{red}{{y}_{1}}\right) = \textcolor{b l u e}{m} \left(x - \textcolor{red}{{x}_{1}}\right)$

Where $\textcolor{b l u e}{m}$ is the slope and $\textcolor{red}{\left(\left({x}_{1} , {y}_{1}\right)\right)}$ is a point the line passes through.

The problem has provided the slope and a point so we can substitute to obtain:

$\left(y - \textcolor{red}{- 3}\right) = \textcolor{b l u e}{- \frac{5}{8}} \left(x - \textcolor{red}{1}\right)$

$\left(y + \textcolor{red}{3}\right) = \textcolor{b l u e}{- \frac{5}{8}} \left(x - \textcolor{red}{1}\right)$