How do you write the quadratic function in intercept form given x intercepts 3,9 and point (14,77)?

1 Answer
Dec 10, 2017

#y=7/5(x-3)(x-9)#

Explanation:

#"given x-intercepts (zeros) say "x=c,x=d#

#"then the factors are "(x-c)" and "(x-d)#

#"and y is the product of the factors"#

#"here "x=3" and "x=9#

#rArr(x-3)" and "(x-9)" are the factors"#

#rArry=a(x-3)(x-9)larrcolor(blue)"a is a multiplier"#

#"to find a substitute "(14,77)" into the equation"#

#77=a(11)(5)#

#rArra=77/55=7/5#

#rArry=7/5(x-3)(x-9)larrcolor(red)"in intercept form"#